A OUTPUT Valor = Valor ∗ 1.12 FROM Convenio = ‘Único’ AND Convenio = ‘Final’ FOR Paciente;
B SELECT Valor = Valor ∗ 1.12 HAVING Convenio = ‘Único’ AND Convenio = ‘Final’ IN Paciente;
C WRITE Convenio.Valor = Convenio.Valor ∗ 1.12 FROM Paciente.Convenio IN (‘Único’ OR ‘Final’);
D UPDATE Paciente.Valor = Paciente.Valor ∗ 1.12 FROM Convenio = ‘Único’ AND Convenio = ‘Final’;
E UPDATE Paciente SET Valor = Valor ∗ 1.12 WHERE Convenio IN (‘Único’,’Final’);